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The difference between the plates of a parallel plate capacitor is 2.0 mm and area of
each plate is 2.0 m2. The plates are in a vacuum. A potential difference of 1.0 x 104 V
is applied across the plates. Find the capacitance.(UHS-2014)
A) 4 x 10-3 F
C) 3.54 x 10-9 F
B) 8.85 x 10-9 F
D) 9.0 x 10-9 F
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If the length width and senaration
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Answers
Answered by
1
Answer:
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Explanation:
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Answered by
1
Answer:
B. 8.85 x 10 -9
Explanation: d = 2 x 10 -3 , Area = 2 m2 , Eo = 8.85x 10-12
formula Capacitance C= Eo . Area / distance between the plates
C = 8.85x 10 -12 . 2 / 2 x 10-3
c= 8.85 x 10 -9
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