Question

11p2 - 14p - 16 plz help fast​

Answer 1

ANSWER✔

$\sf\therefore 11p^2-14p-16$

$\sf\implies 11p^2-14p-16$

$\sf\implies 11p^2+8p-22p-16$

$\sf\implies p(11p+8) - 2(11p-8)$

$\sf\implies (11p+8)(p-2)$

$\large{\boxed{\bf{\implies (11p+8)(p-2)}}}$

$\sf\dashrightarrow 11p+8=0$

$\sf\dashrightarrow p= \dfrac{-8}{11}$

$\sf\dashrightarrow p-2=0$

$\sf\dashrightarrow p=2$

$\sf\therefore the\:zeroes\:are\: 2, \dfrac{-8}{11}$

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Answer 2

Answer:

➡11p² −14p−16

=>11p²−14p−16

=> 11p²+8p-22p-16

=> p(11p+8)−2(11p−8)

=> (11p+8)(p−2)✔

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Step-by-step explanation:

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