Question

11th main i and ii in the paper​

Answer 1

ok............................

Answer 2

Simplify:

Step-by-step explanation:

$\ In \ the \ given \ image \ two \ question \ is$ $\ declared \ that \ is \ as \ follows:$

i)  $(-5 a b^2) (3 a^2 b^2 )( a^5 b)$

ii)  $(2ab)^2 (3 a^2 b)^3$

$\ Simplification \ to \ the \ above \ question \ as \ follows:$

$\ In \ question \ number \ (i):$

$(-5 a b^2) (3 a^2 b^2 )( a^5 b)$

$\ first \ we \ remove \ the \ brackets:$

$-5 \cdot a \cdot b^2 \cdot 3 \cdot a^2 \cdot b^2 \cdot a^5 \cdot \ b$

$-15 {a}^8{b}5$

$\ In \ question \ number \ (ii):$

$(2ab)^2 (3 a^2 b)^3$

$\ Calculate \ value \ and \ remove \ brackets:$

$(2)^2 \cdot a^2 .b^2 \cdot (3)^3\cdot (a^2)^3 \cdot b^3$

$4a^2b^2 \cdot 27a^5b^3$

$108a^7b^5$

So, the simplification of i and ii number is: $-15 {a}^8{b}5$ and $108a^7b^5$

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