Question

11th maths chapter 2​

Answer 1

Answer:

its simple :D

Simple

Step-by-step explanation:

solve L.H.S first

(tan∅+1/cos²∅)²+(tan∅-1/cos∅)²

=tan²∅+1/cos²∅+ 2tan∅/cos∅+tan²∅+1/cos²∅-2tan∅

2tan∅ and -2tan∅ will get cancelled

=2tan²∅ + 2/cos²∅

taking 2 as common we get

=2(tan²∅ + 1/cos²∅)

now tan²∅ can be written as sin²∅/cos²∅ [identity]

=2(sin²∅/cos²∅ + 1/cos²∅)

taking L.C.M as cos²∅ we get

=2(sin²∅ +1/cos²∅)

now cos²∅ can be written as 1-sin²∅ [identity]

=2(sin²∅ +1/1 -sin²∅)

LHS=RHS

∴Proved

thx

Hope you understood it :D pls vote if u like it

Answer 2

Answer:

thanks thanks thanks thanks thanks thanks thanks thanks thanks thanks thanks