Question

11th maths chapter 2​

Answer 1

Step-by-step explanation:

LHS

=(sin³A+cos³A)(sinA-cosA)+(sin³A-cos³A)(sinA+cosA)/sin²A-cosA

=sin⁴A-sin³AcosA+cos³AsinA-cos⁴A+sin⁴A+sin³AcosA-cos³AsinA-cos⁴A/sin²A-cosA

=2(sin⁴A-cos⁴A)/sin²A-cos²A

=2(sin²A+cos²A)(sin²A-cos²A)/sin²A-cos²A

=2

Answer 2

Answer:

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