11th physic chapter 2 scalars and vector
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Torque =r×F [cross product of r and F]
Cross product is found out using determinant:
T= |i j k |
|4 2 -1 |
|-1 -3 1 |
⇒ i(2-3)-j(4-1)+k(-12+2)
= -i - 3j+10k
|T|=√(-1²)+(-3²)+(-10²)
=√1+9+100
=√110
Torque action= √110 Nm
Cross product is found out using determinant:
T= |i j k |
|4 2 -1 |
|-1 -3 1 |
⇒ i(2-3)-j(4-1)+k(-12+2)
= -i - 3j+10k
|T|=√(-1²)+(-3²)+(-10²)
=√1+9+100
=√110
Torque action= √110 Nm
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