Question

. 11th term of the A.P., : -3, - 1/2, 2,... is :​

Answer 1

Answer:

22

Step-by-step explanation:

Given : A.P. : - 3, - 1/2, 2 ....

From the above A.P., we can get the following information,

First term, ${\sf{a_1}}$ = - 3

Second term, ${\sf{a_2}}$ = - 1/2

Third term, ${\sf{a_3}}$ = 2

Common Difference, d = ${\sf{a_2 - a_1}}$

= (- 1/2) - (- 3)

= - 1/2 + 3

d = 5/2

The requires formula to find out the 11th term of the above A.P. is :

→ ${\sf{a_n}}$ = ${\sf{a_1}}$ + d(n - 1)

Putting known values, we get

→ ${\sf{ {a}_{11} }}$ = - 3 + 5/2(11 - 1)

→ ${\sf{ {a}_{11} }}$ = - 3 + 5/2(10)

→ ${\sf{ {a}_{11} }}$ = - 3 + 50/2

→ ${\sf{ {a}_{11} }}$ = - 3 + 25

→ ${\sf{ {a}_{11} }}$ = 22

Answer 2

Here is the answer ! Hope it helps..