11th term of the AP: -3, -1/2, 2, . . . , is?
Sorry for the wrong Question! My bad!
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Given Series is -3, -1/2, 2, .
Here,
a = -3
d = (-1/2) - (-3)
= (-1/2) + 3
= (5/2)
Now,
an = a + (n - 1) * d
= -3 + (11 - 1) * (5/2)
= -3 + (10) * (5/2)
= -3 + 25
= 22
Therefore, 11th term is 22.
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