Question

11thp me term of the arithmetic sequence 3,8,13,18,

Answer 1

Step-by-step explanation:

The given sequence is 3, 8, 13, 18, ....78.

'a' = 3, 'd' = 5, last term = 78, 'n' = ?

tn=a+(n−1)d⟹78=3+(n−1)5⟹78=3+5n−5⟹78=5n−2⟹5n=80orn=16.

The 16th term is 78.

Answer 2

Answer:

according to the question

first term ( a) =3 , common difference (d)=5

11th term=a(n-1)d

11th term=3(11-1)5

a11 =150