Question

11x^2 - 5√11x + 6 = 0
solve by factorization method. ​

Answer 1

Step-by-step explanation:

$11 {x}^{2 } - 5 \sqrt{11} x - 6 = 0 \\ 11 {x }^{2} - 6 \sqrt{11} x + \sqrt{11} x - 6 = 0 \\ \sqrt{11} x( \sqrt{11} x - 6) + 1( \sqrt{11}x - 6) = 0 \\( \sqrt{11} x - 6)( \sqrt{11} x + 1) = 0 \\ \sqrt{11} x - 6 = 0 \\ x = \frac{6}{ \sqrt{11} } \\ \sqrt{11} x + 1 = 0 \\ x = \frac{ - 1}{ \sqrt{11} }$

$x = \frac{6}{ \sqrt{11} } and \: \frac{ - 1}{ \sqrt{11} }$