Question

11x-8y=27 3x+5y=-7 cross multiplcation​

Answer 1

Answer:

Let's say you want to get rid of the "x's"

Multiply the 1st equation by "3" and the 2nd equation by "-11":

33x-24y=81

-33x-55y=+77

Now add the equations to get:

-79y=158

y=-2

Substitute that back into either of the origiinal equations and

solve for "x":

3x+5(-2)=-7

3x-10=-7

3x=3

x=1

Solution is x=1;y=-2

Check it out in the "other" original equation:

11(1)-8(-2)=27

11+16=27

27=27

Answer 2

Step-by-step explanation:

Representing the given equations in standard form

2x−5y=4⇒2x−5y−4=0........(1)

3x−8y=5⇒3x−8y−5=0.........(2)

Using cross-multiplication method to solve the above equations

(−5)(−5)−(−8)(−4)

x

=

(−4)(3)−(−5)(2)

y

=

(2)(−8)−(3)(−5)

1

⟹

25−32

x

=

−12+10

y

=

−16+15

1

−7

x

=

−2

y

=

−1

1

x=

−1

−7

=7;y=

−1

−2

=2

Solution is (x,y)=(7,2)