Question

11x square _26x-21is equal to 0 by factorisation method

Answer 1

$Simplifying \\ \: 11 {x}^{2} + -26x + -21 = 0 \\ \: \: Reorder \: the \: terms: \: \\ -21 + -26x + 11 {x}^{2} = 0 \: \\ Solving \: -21 + -26x + 11 {x}^{2} = 0 \: \\ \\ Solving \: for \: variable \: 'x'. \\ \: Factor \: \: a \: trinomial. \\ \\ \: (-7 + -11x) \: (3 + -1x) \: = \: 0 \\ \\ \: Sub \: problem \: 1 \\ \\ \\ \: Set \: the \: factor \: '(-7 + -11x)' \: equal \: to \: zero \: and \: attempt \: to \: solve: \\ \\ \: Simplifying \: -7 + -11x = 0 \: \\ Solving \: -7 + -11x = 0 \\ \: \\ Move \: all \: terms \: containing \: x \: to \: the \: left, \: all \: other \: terms \: to \: the \: right. \: \\ \\ Add \: '7' \: to \: each \: side \: of \: the \: equation. \: \\ -7 + 7 + -11x = 0 + 7 \: Combine \: like \: terms: \: -7 + 7 = 0 0 + -11x = 0 + 7 -11x = 0 + 7 \: \\ \\ Combine \: like \: terms: \\ \\ \: 0 + 7 = 7 -11x = 7 \: \\ \\ Divide \: each \: side \: by \: '-11' \\ x = -0.6363636364 \: \\ \\ Simplifying \\ \: x = -0.6363636364 \: \\ \\ Sub \: problem \: 2 \: \\ \\ \\ Set \: the \: factor \: '(3 + -1x)' \: equal \: to \: zero \: and \: attempt \: to \: solve: \: \\ \\ Simplifying \\ \: 3 + -1x = 0 \\ \\ \: Solving \: \\ 3 + -1x = 0 \: \\ \\ Move \: all \: terms \: containing \: x \: to \: the \: left, \: all \: other \: terms \: to \: the \: right. \: \\ \\ Add \: '-3' \: to \: each \: side \: of \: the \: equation. \\ \: 3 + -3 + -1x = 0 + -3 \: Combine \: like \: terms: \: 3 + -3 = 0 0 + -1x = 0 + -3 -1x = 0 + -3 \: \\ \\ Combine \: like \: terms: \: \\ 0 + -3 = -3 -1x = -3 \: \\ Divide \: each \: side \: by \: '-1'. \\ x = 3 \\ \: Simplifying \\ \: x = 3 \: \\ \\ Solution \\ \\ \: x = {-0.6363636364, 3}$