Question

12.0g of calcium carbonate was heated till no further loss in weight and 5.28g of carbon dioxide was produced . the mass of the residue calcium oxide was found to be 6.72g . show thatthese observations are in accordance with the law of conservation of mass​

Answer 1

Calcium Carbonate (CaCO3) is used as an important reinforcing filler in the plastic and thermoplastic industry. It can improve the mechanical properties and overall performance of composites, as well as reduce costs.

Answer 2

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$CaCO_3\rightarrow CaO+CO_2$

mass of calcium carbonate= 12.0 g

mass of residue calcium oxide  = 6.72 g

mass of carbon dioxide = 5.28 g

Thus mass or reactants = 12.0 g

Mass of product = Mass of calcium oxide+ mass of carbon dioxide= 6.72 + 5.28 = 12.0 g

Thus the total mass of reactants is equal to the total mass of products.

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