Question

12^-1*10^3*3^-3/
2^-3*25*9^-2

In this I can write 25 as 5^2,
9^-2 as 3^-4,
But how do I do that with 12 and 25?

Answer 1

Answer:

the up one is called power

Step-by-step explanation:

12×12×10×10×10×-3×-3×-3× then multiply it

next step multiply 2×2×2×25×9×9 then multiply it

thank you

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Answer 2

Answer:

$\frac{ {12}^{ - 1} \times {10}^{3} \times {3}^{ - 3} }{ {2}^{ - 3} \times 25 \times {9}^{ - 2} } = \frac{ {2}^{3} \times {9}^{2} \times {10}^{3} }{12 \times {3}^{3} \times 25 } \\ = \frac{ {2}^{3} \times { ({3}^{2}) }^{2} \times {(2 \times 5)}^{3} }{4 \times 3\times {3}^{3} \times {5}^{2} } \\ = \frac{ {2}^{3} \times { 3 }^{4} \times {2}^{3} \times {5}^{3} }{ {2}^{2} \times {3}^{4} \times {5}^{2} } \\ = \frac{ {2}^{6} \times {3}^{4} \times {5}^{3} }{ {2}^{2} \times {3}^{4} \times {5}^{2} } \\ = {(2)}^{6 - 2} \times {(3)}^{4 - 4} \times {(5)}^{3 - 2} \\ = {2}^{4} \times {3}^{0} \times {5}^{1} \\ = 16 \times 1 \times 5 \\ = 80$

Here's the answer to the question.