Question

12 117. A ball of mass 2g moving with a velocity of 2m/s- collides with another ball of mass 8g which is at rests and comes to rest after collission. Then the coefficient of restitution is 1 2) 0.75 3) 0.5 4) 0.25

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Answer 1

$\huge{\underline{\underline{\bf{ SoLuTiOn\: - }}}}♡$

Let mass of first ball be m i.e. m1=m

Mass of second ball  m2=2m

Velocity of first ball before collision  u1=2 m/s

Velocity of second ball before collision  u2=0 m/s

Given :  e=0.5

So, velocity of first ball after collision  v1=m1+m2(m1−em2)u1+(1+e)m2u2

∴   v1=m+2m[m−0.5(2m)](2)+(1+0.5)(2m)(0)=0m/s

Velocity of second ball after collision  v2=m1+m2(m2−em1)u2+(1+e)m1u1

∴   v2=m+2m[2m−0.5m](0)+(1+0.5)(m)(2)=1m/s

Tumko koi or naam nhi mila moti

Answer 2

Step-by-step explanation:

Correct option is

0,1

Let mass of first ball be m i.e. m

1

=m

Mass of second ball m

2

=2m

Velocity of first ball before collision u

1

=2 m/s

Velocity of second ball before collision u

2

=0 m/s

Given : e=0.5

So, velocity of first ball after collision v

1

=

m

1

+m

2

(m

1

−em

2

)u

1

+(1+e)m

2

u

2

∴ v

1

=

m+2m

[m−0.5(2m)](2)+(1+0.5)(2m)(0)

=0m/s

Velocity of second ball after collision v

2

=

m

1

+m

2

(m

2

−em

1

)u

2

+(1+e)m

1

u

1

∴ v

2

=

m+2m

[2m−0.5m](0)+(1+0.5)(m)(2)

=1m/s

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