√12+√12+√12+.....= x. put the value of x
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0
Answer:
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Step-by-step explanation:
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Answered by
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Answer:
X=4 or X= -3
Step-by-step explanation:
I have understood the question as
√(12+√(12+√(12+......))) = X
Squaring both sides,
(12+ √(12+√(12+......)) = X^2
12 + X = X^2
X^2 - X - 12 = 0
X^2 - 4X +3X -12 = 0
X(X-4) +3(X-4)=0
(X - 4) (X + 3) =0
X=4 or X= -3
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