Question

З^а + 12а + 12
$3a {}^{2} + 12a + 12$
please solve it​

Answer 1

Answer:

Answer: The value of 6(2b-4) is 36.

Step-by-step explanation:

Given expression: 6(2b-4)

To find the value of 6(2b-4)at b= 5, we need to substitute the b=5 in the expression, we get

6(2(5)-4)\=6(10-4).......[ ext{solve parentheses}]\=6(6)\=6 imes6=36

\Rightarrow6(2(5)-4)=36

Therefore, the value of 6(2b-4) is 36, when b=5.

Answer 2

Required Answer:-

Given to factorise:

• 3a² + 12a + 12

Solution:

We have,

3a² + 12a + 12

Here,

a = 3

b = 12

c = 12

➡ ac = 36

We need to split b into two parts x and y such that,

➡ x + y = 12

➡ xy = 36

We can see that,

➡ 6 + 6 = 12 and,

➡6 × 6 = 36

So,

3a² + 12a + 12

= 3a² + 6a + 6a + 12

= 3a(a + 2) + 6(a + 2)

= (3a + 6)(a + 2)

= 3(a + 2)(a + 2)

= 3(a + 2)²

Hence, the factorised form of the polynomial is 3(a + 2)²

Answer:

• The factorised form of the polynomial is 3(a + 2)².