Physics, asked by gauridixit197, 1 month ago

12 122. The velocity-time graph of an object is shown. The distance during the interval 0 to t, is :- С. 0. t₂ (1) Area A + Area B + Area C + Area D + Area E (2) Area A + Area C - Area B - Area D (3) Area A + Area B + Area C + Area D (4) Area A + Area C + Area E - Area B + Area D​

Answers

Answered by agrimkingrevenge
0

Answer:

Between time interval 20 s te 40 s, there is non-zero acceleration and retardation. Hence, distance travelled during this interval

= Area between time interval 20 s to 40 s

=

2

1

×20×3+20×1=30+20=50m

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