12/130 is it terminating decimal
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we can find whether a number is terminating or non terminating by factorising the denominator of the required number.
so here the denominator is 130 , it's prime factorisation will be =2×5×13
since the prime factors of the denominator also includes 13 so this we can conclude that it is not terminating i.e. it is Mon terminating decimal(since the number which has a terminating decimal expansion has it's denominator's prime factorisation in the form 2^m or 5^n or both where n and m are natural numbers).
thank u hope it helps!^_^
so here the denominator is 130 , it's prime factorisation will be =2×5×13
since the prime factors of the denominator also includes 13 so this we can conclude that it is not terminating i.e. it is Mon terminating decimal(since the number which has a terminating decimal expansion has it's denominator's prime factorisation in the form 2^m or 5^n or both where n and m are natural numbers).
thank u hope it helps!^_^
Answered by
3
Heya!
Here is yr answer......
If the denominator of the no. is in the form 2^n × 5^m. Then it is said to be a terminating decimal!
=> 12/130
=> 12/2×5×13
Itis non-terminating repeating decimal
Hope it hlpz..
Here is yr answer......
If the denominator of the no. is in the form 2^n × 5^m. Then it is said to be a terminating decimal!
=> 12/130
=> 12/2×5×13
Itis non-terminating repeating decimal
Hope it hlpz..
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