Question

1²+2²+3²____30² term​

Answer 1

Answer:

9455

Step-by-step explanation:

The formula to find sum of first n terms of a sequence of squares of natural numbers =

n(n + 1)(2n + 1) / 6

Here n = 30

Sum = 30(30 + 1)(2*30 + 1) / 6

= (30 * 31 * 61) /6

= 56730 / 6

= 9455