Question

1²+2²+3²____30² term​

Answer 1

Answer:

The general formula for :

1^2 +2^2 + 3^2 +4^2…….+n^2=(n)(n+1)(2n+1)/6

So the ans to the given ques can be found out by substituting 25 in the above formula which gives :

1^2 + 2^2 +…….25^2=(25)(25+1)(2×25+1)/6=(25×26×51)/6

Therefore the ans to the given series will be 5525.