Math, asked by mallikladukishor, 9 months ago

1²+2²+3²....n²=n(n+1)(2n+1)/6​

Answers

Answered by shamsisme
4

Answer:

1²+2²+3²....n²=n(n+1)(2n+1)/6​

Step-by-step explanation:

1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​1²+2²+3²....n²=n(n+1)(2n+1)/6​

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