1²+2²+3²....n²=n(n+1)(2n+1)/6
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Answer:
1²+2²+3²....n²=n(n+1)(2n+1)/6
Step-by-step explanation:
1²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/61²+2²+3²....n²=n(n+1)(2n+1)/6
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