Question

12.
2m +5
= 3m-10
3 solve the equation.check your result​

Answer 1

The above question can be written as,

= 3 × [(2m + 5)/ 3] = 3 × (3m -10) … [Multiplying both side by 3]

= (2m + 5) = 9m – 30

Transposing 2m to RHS and it becomes

-2m and -30 to LHS it becomes 30

= 30 + 5 = 9m -2m

= 35 = 7m

Multiplying both side by (1/7),

= 7m × (1/7) = 35 × (1/7)

= m = (35/7)

= m = 5

By substituting 5 in the place of m in given equation, we get

LHS,

= 2m + 5

= 2 × (5) + 5

= 10 + 5

= 15

RHS,

= 9m – 30

= 9 × (5) – 30

= 45 – 30

= 15

By comparing LHS and RHS

= 15 = 15

∴ LHS = RHS

Hence, the result is verified.

Answer 2

Answer:

m =-15

I think Iam correct

Step-by-step explanation:

2m + 5=3m-10

3m-2m=-10-5

m=-15