Question

12(2x-3y)² -16(3y-2x)​

Answer 1

Given: The equation is 12(2x-3y)² -16(3y-2x)

We have to solve the above equation.

• By using the Bodmas rule, we are solving the above equation.
• As we know that the Bodmas stands for,
• B-Brackets,
• O-Orders (powers/indices or roots),
• D-Division,
• M-Multiplication,
• A-Addition,
• S-Subtraction.
• And the Bodmas rule is the mathematical expressions with multiple operators need to be solved from left to right in the above order.

We are solving in the following way:

We have,

$12(2x-3y)² -16(3y-2x).$

$= 12 ( 4 {x}^{2} - 12xy + 9 {y}^{2}) -48y + 32x) \\ \\ = 48 {x}^{2} - 144xy + 108 {y}^{2} - 48y + 32x$

Hence the solution of the above equation is

$48 {x}^{2} - 144xy + 108 {y}^{2} - 48y + 32x$