Math, asked by pkvortex08, 1 year ago

12 (2x-3y)^2-16 (3y-2x) factorise it

Answers

Answered by siddhartharao77
12
Given, 12(2x-3y)^2-16(3y-2x)

= 12(3y-2x)^2-16(3y-2x)

= 4(3y-2x)(3(3y-2x)-4)

= 4(3y-2x)(9y-6x-4).

Hope this helps!
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