12/√3+√5-√2
rationalize the denominator
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Step-by-step explanation:
12÷√3+√5-√2=12(√3+√5-√2)÷(√3+√5-√2)(√3-√5+√2)
=12√3+12√5-12√2÷(√3*√3+√5*-√5+-√2*√2)
= 12(√3+√5+√2)÷(3-5-2)
=12(√3+√5+√2)÷-4
=-3(√3+√5+√2)
MAYBE CORRECT
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