Question

12. 3 - [x - {2y - (5x + y - 3) + 2x²} - (x² – 3y)]​

Answer 1

Answer:

12.3-[x-{2y-(5x+y-3)+2x²}-(x²-3y)]

=x-(2y-5x-y+3+2x²)-(x²-3y)

=6x+2y-3-3x²

Answer 2

Step-by-step explanation:

3-x-{2y-5x-y+3+2x²}-x²-3y

=6-6x-2y+3x²