Question

12^33×34^33×2^70 sum of factors

Answer 1

Answer:

Step-by-step explanation:

2^70

Answer 2

12^33*34^23*2^70 = (3*4)^33 * (2*17)^23 * 2^70 = 3^33 * 17^23 * 2^(70+66+23) =

= 3^33 * 17^23 * 2^159

Now, any factor should have from 0 to 33 times the number 3, from 0 to 23 times the prime 17 and from 0 to 159 the prime 2… but, in case it has number 2 more than 0 times then it would be an even factor, not odd.

So, there are 34*24 odd factors, that is, 68*12=136*6 = 272*3 = 816

Step-by-step explanation: