Question

12, 36, 150, 392, 1452, __. find the missing
A) 2452
B)2197
C)2246
D)2366​

Answer 1

Answer:

(D) 2366

Step-by-step explanation:

12,36.150. 392, 1452, -----,

Each number obtained is square of prime number multiplied by (the prime number + 1).

2² . (2+1) , 3² . (3+1) , 5². (5+1) , 7². (7+1), 11² . (11+1)

So the next prime number is 13 and the missing  number is 13² . (13+1)   = 2366

Answer 2

d)2366 is the missing term.

12, 36, 150, 392, 1452, 2366

Step-by-step explanation:

Given:

12, 36, 150, 392, 1452, _

To find:

The missing number

Solution:

• This series is a numerical sequence in which the numbers are arranged orderly and make a sequence.
• The pattern is (x₁,x₂,x₃,x₄,x₅,x₆) are the numbers in the series thus (2²+2³)⇒x₁, (3²+3³)⇒x₂, (5²+5³)⇒x₃, (7²+7³)⇒x₄, (11²+11³)⇒x₅, (13²+13³)⇒x₆.
• The pattern of this series is the formation of prime numbers series from (2,3,5,7,11,13).

The first number x₁ is obtained by the square and cubic term of number 2 and adding the terms.

(2²+2³)⇒x₁

          ⇒(4+8)

          x₁⇒12

The second number x₂ is obtained by square and cubic term of number 3 and add the terms.

(3²+3³)⇒x₂      

         ⇒(9+27)

         x₂⇒36

The third number x₃ is obtained by square and cubic term of number 5 and add the terms.

(5²+5³)⇒x₃  

          ⇒25+125

         x₃ ⇒150

The fourth number x₄ is obtained by square and cubic term of number 7 and add the terms.

( 7²+7³)⇒x₄,

         ⇒49+343

        x₄ ⇒392

The fifth number x₅ is obtained by square and cubic term of number 11 and add the terms.

(11²+11³)⇒x₅      

          ⇒121+1331

          x₅⇒1452

The sixth number x₆ is obtained by square and cubic term of number 13 and adds the terms.

(13²+13³)⇒x₄,

         ⇒169+2197

        x₆ ⇒2366

Hence,

The next number in the series is 2366.

12, 36, 150, 392, 1452, 2366.