Question

12. (3x^2 - 2x +3)*(x+2) =​

Answer 1

Equation to be solved :

(3x²-2x+3)(x+2)

Solution :-

= (3x²-2x+3)(x+2)

= 3x³+6x²-2x²-4x+3x+6

= 3x³+4x²-x+6

Answer 2

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$( {3x}^{2} - 2x + 3) \times (x + 2)$

First, We will multiply the equation with x

$( {3x}^{2} - 2x + 3) \times x$

${3x}^{3} - {2x}^{2} + 3x$

Now with 2

$( {3x}^{2} - 2x + 3) \times 2$

${6x}^{2} - 4x + 6$

Now combine the equation!

${3x}^{3} - {2x}^{2} + 3x + {6x}^{2} - 4x + 6$

${3x}^{3} + {6x}^{2} - {2x}^{2} - 4x + 3x + 6$

${3x}^{3} + {4x}^{2} - x + 6$

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