Math, asked by chandan110285, 1 month ago

12-[4÷2+{3÷(1-1_3)}]

Answers

Answered by shivangipati11601

0

Answer:

12-[4÷2+{3÷(1-1-3)}]

=>12-[4÷2+{3÷(1+2)}]

=>12-[4÷2+{3÷3}]

=>12-[4÷2+1]

=>12-[2+1]

=>12-3

=>9

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