Question

12/4√3-√2 rationalize the denominator

Answer 1

$\huge\underline\mathcal{Answer:-}$

$\frac{12}{4 \sqrt{3} - \sqrt{2} } \\ = \frac{12}{4 \sqrt{3} - \sqrt{2} } \times \frac{4 \sqrt{3 } + \sqrt{2} }{4 \sqrt{3} + \sqrt{2} } \\ = \frac{48 \sqrt{3} + 12 \sqrt{2} }{48 - 2} \\ = \frac{48 \sqrt{3} + 12 \sqrt{2} }{46}$

Answer 2

Step-by-step explanation:

4

3

−

2

12

=

4

3

−

2

12

×

4

3

+

2

4

3

+

2

=

48−2

48

3

+12

2

=

46

48

3

+12

2