12,5,13 form a Pythagorean triplet
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Answered by
2
hyp sq. =side sq. +side sq.
13 sq. =12 sq. +5 sq.
169=144+25=169
Therefore proved
13 sq. =12 sq. +5 sq.
169=144+25=169
Therefore proved
Answered by
1
(hyp)^2=(adj)^2+(opp)^2
(13)^2=(12)^2+(5)^2
169=144+25
169=169
(13)^2=(12)^2+(5)^2
169=144+25
169=169
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