Math, asked by sahoo19, 5 months ago

12:57
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The Laplace transform of
1 - cos2t/
t
is
Select one:​

Answers

Answered by UniversalSwapnil
3

Answer:

F[t]=1 + cos 2t /t , the L[1] = 1/s or

L[1/t] = integral of du/u = ln u from s to infinity has no limit , likewise

L[cos 2t ] = s/[s^2+ 4]

L[( cos 2t)/t] = integral of L[cos 2t ] from s to infinity

= integral of [ u du/[u^2 +4] from s to infinity

This integral does not converge so the

L[(cos 2t)/t] does not exist

L[ F(t)] does not exist

Step-by-step explanation:

thanks

Answered by rahulshrivastav39200
1

Answer:

Step-by-step explanation:

I think this the correct answer. Please support me if you find useful

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