12:57
Flag question
The Laplace transform of
1 - cos2t/
t
is
Select one:
Answers
Answered by
3
Answer:
F[t]=1 + cos 2t /t , the L[1] = 1/s or
L[1/t] = integral of du/u = ln u from s to infinity has no limit , likewise
L[cos 2t ] = s/[s^2+ 4]
L[( cos 2t)/t] = integral of L[cos 2t ] from s to infinity
= integral of [ u du/[u^2 +4] from s to infinity
This integral does not converge so the
L[(cos 2t)/t] does not exist
L[ F(t)] does not exist
Step-by-step explanation:
thanks
Answered by
1
Answer:
Step-by-step explanation:
I think this the correct answer. Please support me if you find useful
Attachments:

Similar questions