Question

12/58y³z² by -36/29yz​

Answer 1

Answer:

-1/6 $y^{2} z$

Step-by-step explanation:

$(\frac{12}{58})$ $y^{3} z^{2}$by $(\frac{-36}{29})$$y^{1}z^{1}$

($\frac{12X29}{58X(-36)}$  $y^{3-1} z^{2-1}$

$\frac{1}{-6}$ $y^{2} z$  answer