12/625,State whether given rational number have terminating decimal expansion or not and if it has terminating decimal expansion, find it.
Answers
Answered by
14
If the factors of denominator of the given rational number is of form 2ⁿ 5^m ,where n and m are non negative integers, then the decimal expansion of the rational number is terminating otherwise non terminating recurring.
SOLUTION:
12/625
13 / (5⁴)
Here, the factors of the denominator 625 are are 5⁴ which is in the form 2ⁿ 5^m .
Hence , 12/625 has terminating decimal expansion and can be expressed as
12/625 = 12 × 2⁴ / (5⁴ × 2⁴)
= 12 × 16 / (2×5)⁴ = 192 /10000
= 0.0192
Hence, the decimal expansion of 12/625 = 0.0192
HOPE THIS ANSWER WILL HELP YOU...
Answered by
5
Hi ,
12/625
= 12/5⁴
Here ,
Denominator ( q ) = 5⁴ , which is of the
form 2^n × 5^m ( n = 0 and m = 4 ) .
So , the rational number 12/625 has
a terminating decimal expansion .
12/625
= 12/5⁴
= ( 12 × 2⁴ )/( 2⁴ × 5⁴ )
= 192/( 10⁴ )
= 0.0192
( terminating decimal )
I hope this helps you.
: )
12/625
= 12/5⁴
Here ,
Denominator ( q ) = 5⁴ , which is of the
form 2^n × 5^m ( n = 0 and m = 4 ) .
So , the rational number 12/625 has
a terminating decimal expansion .
12/625
= 12/5⁴
= ( 12 × 2⁴ )/( 2⁴ × 5⁴ )
= 192/( 10⁴ )
= 0.0192
( terminating decimal )
I hope this helps you.
: )
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