Question

12. 7y^2 - 30y = 2y-16
solve the following quadratic equation by factorisation​

Answer 1

Answer:

y = 4 OR y = 4/7

Step-by-step explanation:

7y² - 30y = 2y - 16

7y² - 30y - 2y + 16 = 0

7y² - 32y +16 = 0

7y² - 28y - 4y + 16 = 0

7y ( y - 4 ) - 4 ( y - 4 ) = 0

(y - 4) (7y - 4) = 0

Answer 2

Answer:

The possible values of y are 4 and

$\frac{4}{7}$

Step-by-step explanation:

$7 {y}^{2} - 30y = 2y - 16$

$7 {y}^{2} - 32y + 16 = 0$

$7 {y}^{2} - 4y - 28y + 16 = 0$

$y(7y - 4) - 4(7y - 4) = 0$

$(7y - 4)(y - 4) = 0$

$y = \frac{4}{7} \: and \: y = 4$