Question

12.9.21 Prove that the points (0,-5), (4,3) and (-4,-3) lie on the circie centred at the origin with radius 5​

Answer 1

Answer:

Distance from center to point on circle must be equal & equal to radius

A=(0,−5)B(4,3)C(−4,−3)O(0,0)

AO=

5

2

​

   BO=

3

2

+4

2

​

   CO=

3

2

+4

2

5

2

​

   BO=

3

2

+4

2

​

   CO=

3

2

+4

2

​

Hence CE(0,0) is the center with a radius of 5.