12
9. If 4 tan 0=3 then prove that sin Ocos e
25
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0
tan0=3/4
3=perpendicular
4=base
hypotenuse= root under 4 square +3 square
h=5
sin0=p/h=3/5
cos0=b/h=4/5
3/5*4/5=12/25
Answered by
0
Answer:
AB=3
BC=4
AC=?
AC=√AB+BC
AC=√3+4
AC=√9+16
AC=√25
AC=5
,
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