Question

12 + 9 √[(x - 1)(3x + 2)]= 3x² - x.
solve for x​

Answer 1

Answer:

$12 + 9 \sqrt{(x - 1)(3x + 2 } = 3 {x }^{2} - x \\ 12 + 9 \sqrt{3 {x + 2x - 3x - 2}^{2} } = 3 {x}^{2} - x \\ 12 + 9 \sqrt{2} = 0$