Question

12 ( a+1 ) ² - 25 ( a+1 ) ( b+2 ) +1​

Answer 1

Answer:

Let [(a + 1) = x ] and [(b + 2) = y ].

=) 12x² - 25xy +12y²

Splitting [25xy as ( 16 + 9)xy ].

=) 12x² - ( 16 + 9 )xy + 12y²

=) 12x² - 16xy - 9xy + 12y²

=) 4x (3x - 4y) - 3y (3x - 4y)

=) (3x - 4y) (4x - 3y)

Now,

Substituting the assumed value. we get,

=) [3(a + 1) - 4( b +2)] [ 4( a + 1) - 3(b +2)]

=) [3a + 3-4b-8] [ 4a + 4- 3b - 6]

=) [3a - 4b - 5 ] [ 4a - 3b - 2 ]

Answer 2

Step-by-step explanation:

12(+1)2−25(+1)(+2)+1

12\left(a+1\right)^{2}-25(a+1)(b+2)+1q12(a+1)2−25(a+1)(b+2)+1q

12(+1)(+1)−25(+1)(+2)+1

122−25−26−25+−38

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