Question

12.A 1.5m tall man, standing at the foot of a tower sees the top of hill 40 metres away at an

elevation of 55°. Climbing to the top of the tower ,he sees it at elevation of 50°.

a)Draw a rough figure

b)Calculate the height of the tower and hill?

[Sin 55=0.81, Sin 50=0.76, Cos 55=0.57, Cos 50=0.64]​

Answer 1

Step-by-step explanation:

ANSWER

Height of the building =PQ

Height of the tower =AC

The distance between the building and the tower, AP=50m

From the right △BRQ

RQ=BR×tan60o=50×1.73=86.5

PQ=PR+RQ=1.7+86.5=88.2

Thus, the height of the builiding is about 88.2 metres.

From right △DTQ

QT=DT×tan50o=50×1.19=59.5

AC=PS=PQ(QT+TS)

⇒ AC=88.2−(59.5+1.7)

⇒ AC=88.2−61.2=27m

Thus, the height of the tower is about 27 metres