Question

12.a/3=b/4=c/7,show that a+b+c/c=2​

Answer 1

Answer:

a=3k,b=4k,c=7k where k is the common factor.

(a+b+c) /c=(3k+4k+7k)/7k=14k/7k=2

Answer 2

"$\frac{(a + b + c)}{c}$ = 2", it is proved

Step-by-step explanation:

Let $\frac{a}{3}$ = $\frac{b}{4}$ = $\frac{c}{7}$ = 7

∴ a = 3k, b = 4k and c = 7k

L.H.S. = $\frac{(a + b + c)}{c}$

=  $\frac{(3k + 4k + 7k)}{7k}$

= $\frac{(14k)}{7k}$

= 2

= R.H.S., it is proved.