Question

12(a+3b) - 8(a+3b)^2 factorise​

Answer 1

Answer:

$\large \boxed{4(3a+9b-2a^2-12ab-18b^2)}$

Step-by-step explanation:

To solve this problem, first you have to use the distributive property of $\displaystyle a(b+c)=ab+ac$. First, expand the form to solve with distributive property. $\displaystyle 12(a+3b)=12a+36b$, $\displaystyle =12a+36b-8(a+3b)^2$. Next, thing to do is solve. $\displaystyle 12a+36b-8(a+3b)^2=\boxed{12a+36b-8a^2-48ab-72b^2}$. Rewrite -72 as 18*4, secondly, rewrite -48 as 12*4, thirdly, rewrite -8 as 2*4, next, rewrite 36 as 9*4, then, rewrite 12 as 3*4. $\displaystyle 3*4a+9*4b+2*4a^2+3*4*4ab+18*4b^2$, then you solve or factor it out by the common term of 4. $\displaystyle 3*4a+9*4b+2*4a^2+3*4*4ab+18*4b^2=\boxed{4(3a+9b-2a^2-12ab-18b^2)}$. $\boxed{\textnormal{Therefore, the correct answer is \boxed{4(3a+9b-2a^2-12ab-18b^2)}}}$.