Question

12. A ball is droped from a building with 40
m see initial speed Height of building is
45 mts and after T seconds distance
between ball and ground level is S = 48 +40t-8t^2then after how many seconds ball
reach the ground​


If anyone answer this I will mark them as brainliest.....

Answer 1

we will put formula v=u+gt please mark as brainliest please