Question

12. A ball rolling down a hill was displaced 19.6 m while uniformly
accelerating from rest. If the final velocity was 5.0 m/s. what was the rate of
acceleration?​

Answer 1

Answer:

Explanation:

Use the kinematic relation

 

vf2 - vi2 = 2ad

 

vf = final speed = 5.00 m/s

vi = initial speed = 0

d = travel distance = 19.6 m

a = constant acceleration = ?

 

a = vf2/(2d) = (5.00)2/[2(19.6)] m/s2 ≅ 0.638 m/s2

Answer 2

Answer:

The acceleration is defined as the rate of change of velocity with respect to time. When the velocity of the particle is increasing (or decreasing) with a constant rate, then the say that the acceleration of the particle is uniform and for such a motion we can use the set of kinematics equations.