Question

12.
A body moving with a constant acceleration
travels the distances 3 m and 8 m respectively in
1 s and 2 s. Calculate : (i) the initial velocity, and
(ii) the acceleration of body.​

Answer 1

Answer:

Using, s=ut+21at2

 s1=u+21a

or, 3=u+2a 

  ∴a=6−2u

s2=2u+21a×4

8=2u+2a

Solving the equations

8=2u+2(6−2u)

8=2u+12−4u 

2u=4 

u=2m/s

∴a=6−2u=6−4=2m/s2