Question

12. A boy has five rupee coins, two rupee coins and one rupee coins in the ratio 3:4:5. If
he has an amount of 224, then find the numbers of one rupee coins with the boy.
a) 40
b) 35
c) 20
d) 30​

Answer 1

Answer:

Let the total number of coins be 12X.

Then,

Number of Rs.5 coins = 3X

Number of Rs.2 coins = 4X

Number of Re.1 coins = 5X

Total value of :-

Rs.5 coins = 3X * 5 = 15X

Rs.2 coins = 4X * 2 = 8X

Re.1 coins = 5X * 1 = 5X

Given, total value of all coins = 224

Therefore,

15X + 8X + 5X = 224

28X = 224

X = 8

Total number of coins = 12X = 12 * 8 = 96

Number of,

Rs.5 coins = (3/12) * 96 = 24 coins

Rs.2 coins = (4/12) * 96 = 32 coins

Re.1 coins = (5/12) * 96 = 40 coins

(Given no. of Rs.5, Rs.2, and Re.1 coins are in the ratio of 3:4:5)

Final Answer : The boy has 40 Re.1 coins.

Let's cross verify the answer once.

(24*5) + (32*2) + (40*1)

= 120 + 64 + 40

= 224 = Value given in the question.

Step-by-step explanation:

Hope this helps you dear mate

Answer 2

Answer:

Hey friend,

Here is the answer you are searching for,

Let ₹5 coins be 3x,

₹2 coins be 4x,

₹1 coins be 5x,

=>₹5 amount = 5×3x = 15x

₹2 amount = 2×4x = 8x

₹1 amount = 1×5x = 5x

=>Total amount = 15x+8x+5x = 28x

Given,

Total amount = ₹224

=>28x = 224

=>x = 8

Therefore,

Number of ₹1 coins = 5×8 = 40

=>Option (a) 40 is the correct answer.

HOPE IT HELPS YOU.

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