Question

12. A bullet of mass 10 g is fired at speed of 500 m/s from the gun of mass 5 kg. What is the recoil velocity
of the gun?
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Answer 1

Explanation:

m1=10g=0.01kg

m2=5kg

u1=u2=0(before firing)

v1=500

v2=?

m1u1+m2u2=m1v1+m2v2

0.01kg*0+5*0=0.01*500+5v2

0=5+5v2

-5=5v2

v2=-5÷5

v2=-1

recoil velocity is -1

Answer 2

Answer:

Mass of bullet -> 10 gm => 0. 01kg

velocity of bullet -> 500m/s

Mass of gun -> 5 kg

recoil velocity of gun ->?

Now we know that momentum get conserved so,

☆ momentum of gun = momentum of bullet

Now,

mass velocity. mass. Recoil

of × of = of × velocity

bullet bullet gun of gun

0. 01 × 500 = 5 × Recoil velocity

Recoil velocit = 5/5

Recoil velocity = 1 m/s