Question

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12. A bullet of mass 10 g strikes a wooden block with a velocity of 300 ms
After penetrating 20 cm into it, its velocity drops to 200 ms. Then
average resistance offered by the block is
1) 125 N 2) 250 N 3) 1250 N 4) 2500 N​

Answer 1

Answer:

work done by all forces = ∆KE

3. 1250N

Explanation:

work =- F× s

∆KE = 1/2m(vf^2 - vi^2)

Answer 2

u 300m/s

v 200m/s

s 20cm= 0.20m

m 10g=0.01kg

3rd equation of motion

2as=v2-u2

reretradration a =-125000m/s

the resitance force F =ma

F=0.01*125000F =1250n

Mark brainliest boiii